Solve the problem.
-The manager of an electrical supply store measured the diameters of the rolls of wire in the inventory. The diameters of the rolls (in meters) are listed below. $$\begin{array} { l l l l l l }
0.229 & 0.119 & 0.465 & 0.406 & 0.596 & 0.29
\end{array}$$
A) 0.477 m
B) 0.119 m
C) 0.465 m
D) 0.061 m

Question

Solve the problem.
-The manager of an electrical supply store measured the diameters of the rolls of wire in the inventory. The diameters of the rolls (in meters) are listed below. $$\begin{array} { l l l l l l } 
0.229 & 0.119 & 0.465 & 0.406 & 0.596 & 0.29
\end{array}$$
A) 0.477 m
B) 0.119 m
C) 0.465 m
D) 0.061 m

Quizplus · Accepted Answer

The mean is the sum of the values divided by the number of values. The mean of the given values is (0.229 + 0.119 + 0.465 + 0.406 + 0.596 + 0.29) / 6 = 2.86 / 6 = 0.477.

Solve the Problem 0.2290.1190.4650.4060.5960.29\begin{array} { l l l l l l } 0.229 & 0.119 & 0.465 & 0.406 & 0.596 & 0.29\end{array}0.229​0.119​0.465​0.406​0.596​0.29​

Solve the Problem $\begin{array} { l l l l l l } 0.229 & 0.119 & 0.465 & 0.406 & 0.596 & 0.29\end{array}$