Find the standard deviation for the given sample data. Round your answer to one more decimal place than is present in
the original data.
-To get the best deal on a CD player, Tom called eight appliance stores and asked the cost of a specific model. The prices he was quoted are listed below: $\begin{array}{|llllllll}
\$ 356 & \$ 169 & \$ 293 & \$ 267 & \$ 386 & \$ 288 & \$ 318 & \$ 275
\end{array}$
A) $721,124.0
B) $691,488.0
C) $65.1
D) $330.5

Question

Quizplus · Accepted Answer

1. Find the mean: $\frac{356+169+293+267+386+288+318+275}{8}=295.5$
2. Find the deviation from the mean for each value: 
$\begin{array}{|llllllll}
60.5 & -126.5 & -2.5 & -28.5 & 90.5 & -7.5 & 22.5 & -20.5
\end{array}$
3. Square each deviation: 
$\begin{array}{|llllllll}
3660.25 & 16006.25 & 6.25 & 812.25 & 8190.25 & 56.25 & 506.25 & 420.25
\end{array}$
4. Add up the squared deviations: $3660.25+16006.25+6.25+812.25+8190.25+56.25+506.25+420.25=29537.5$
5. Divide the sum by $n-1=7$, the sample size minus one: $\frac{29537.5}{7}=4219.64$
6. Take the square root: $\sqrt{4219.64}=64.98\approx 65.1$, rounded to one more decimal place than the original data. Therefore, the standard deviation is $65.1.

Find the Standard Deviation for the Given Sample Data $356$169$293$267$386$288$318$275\begin{array}{|llllllll}\$ 356 & \$ 169 & \$ 293 & \$ 267 & \$ 386 & \$ 288 & \$ 318 & \$ 275\end{array}$356​$169​$293​$267​$386​$288​$318​$275​

Find the Standard Deviation for the Given Sample Data $\begin{array}{|llllllll}\$ 356 & \$ 169 & \$ 293 & \$ 267 & \$ 386 & \$ 288 & \$ 318 & \$ 275\end{array}$