Suppose a sample of 60 business majors revealed that the average time spent studying per week is 22 hours with a standard deviation of 4 hours. For one student
Reporting that he studies 16 hours per week, the corresponding z score is
A) -1.5
B) 1.5
C) 2.2
D) -2.2
E) -3.0

Question

Quizplus · Accepted Answer

The z-score is calculated using the formula $z = \frac{(X - \mu)}{\sigma}$, where $X$ is the value in question, $\mu$ is the mean, and $\sigma$ is the standard deviation. Plugging in the given values, $z = \frac{(16 - 22)}{4} = \frac{-6}{4} = -1.5$.

Suppose a Sample of 60 Business Majors Revealed That the Average