A reaction has the following rate law: Rate = k[A][B]²
In experiment 1, the concentrations of A and B are both 0.10 mol L⁻¹; in experiment 2, the concentrations are both 0.30 mol L⁻¹. If the temperature stays constant, what is the value of the ratio, Rate(2) /Rate(1) ?

Question

Quizplus · Accepted Answer

Given the rate law Rate = k[A][B], if the concentration of both A and B is tripled (from 0.10 to 0.30), the rate increases by a factor of 3^2 = 9, because the rate is directly proportional to the concentration of both A and B, each raised to the first power.

A Reaction Has the Following Rate Law: Rate = K[A][B]2

A Reaction Has the Following Rate Law: Rate = K[A][B]²