Ammonium cyanate (NH4CNO) reacts to form urea (NH2CONH2) . At 65°C the rate constant, k, is 3.60 L mol−1s−1. What is the rate law for this reaction?
A) Rate = 3.60 L mol −1s −1[NH 4CNO]
B) Rate = 3.60 L mol −1s −1[NH 4CNO] 2
C) Rate = 0.28 mol L −1 s −1[NH 4CNO]
D) Rate = 0.28 mol L −1 s −1[NH 4CNO] 2
E) Rate = 3.60 L mol −1s −1[NH 2CONH 2] −1
Correct Answer:
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