A 6.0 Ω resistor and a 3.0 Ω resistor are connected in series to a 1.5 V battery of negligible internal resistance. What is the current in the 3.0 Ω resistor?
A) 2.0 A
B) 0.50 A
C) 0.25 A
D) 0.17 A
E) 0.75 A

Question

Quizplus · Accepted Answer

First, calculate the total resistance in the circuit:
Rtotal = R1 + R2 = 6.0 Ω + 3.0 Ω = 9.0 Ω
Then, use Ohm's Law to calculate the current in the circuit:
I = V/Rtotal = 1.5 V / 9.0 Ω = 0.17 A
Since the resistors are connected in series, the current is the same throughout the circuit. Therefore, the current in the 3.0 Ω resistor is also 0.17 A.

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