Two capacitors of values 6.0 mF and 9.0 mF are connected in series to a 30.0 V power supply. What is the resulting potential difference across the 6.0 mF capacitor?
A) 30 V
B) 18 V
C) 12 V
D) 6.0 V
E) 3.0 V

Question

Quizplus · Accepted Answer

When capacitors are connected in series, the total capacitance is reduced and the voltage across each capacitor is different. To find the voltage across each capacitor, we can use the formula:

V = Vtot * (C / Ctot)

where V is the voltage across the capacitor in question, Vtot is the total voltage of the circuit (30 V), C is the capacitance of the capacitor in question, and Ctot is the total capacitance of the circuit (the sum of the two capacitors).

Using this formula, we can find the voltage across the 6.0 mF capacitor as:

V = 30 V * (6.0 mF / (6.0 mF + 9.0 mF)) = 30 V * (6.0 / 15.0) = 12 V

Therefore, the answer is B) 12 V.

Two Capacitors of Values 6