Consider the reaction: Zn(s)+ NO₃⁻(aq)→ NH₃(aq)+ Zn(OH)₄²⁻(aq)When this equation is balanced in basic solution, the coefficient for water will be ________, and the number of electrons transferred will be ________.

Question

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First, we need to balance the equation: Zn(s) + NO₃⁻(aq) → NH₃(aq) + Zn(OH)₄²⁻(aq) Zn(s) + NO3-(aq) + OH-(aq) → NH3(aq) + Zn(OH)42-(aq) Now, we need to calculate the number of electrons transferred. We can do this by looking at the oxidation states of each element in the equation. Zn(s) has an oxidation state of 0, while Zn(OH)42-(aq) has an oxidation state of -2. This means that Zn has lost 2 electrons. NO3-(aq) has an oxidation state of +5, while NH3(aq) has an oxidation state of -3. This means that each nitrogen atom has gained 4 electrons. Overall, the equation involves the transfer of 2 electrons from zinc to nitrogen. Therefore, the answer is choice C: 6 waters are needed (2 for the hydroxide ions on the reactant side and 4 for the zinc hydroxide on the product side) and 8 electrons are transferred.

Consider the Reaction: Zn(s)+ NO3−(aq)→ NH3(aq)+ Zn(OH)42−(aq)When This Equation Is

Consider the Reaction: Zn(s)+ NO₃⁻(aq)→ NH₃(aq)+ Zn(OH)₄²⁻(aq)When This Equation Is