A sample of gas initially occupies 2.50 L at a pressure of 0.900 atm at 22.0°C. What will the pressure be if the temperature is changed to 56.5°C, and the volume is changed to 1.50 L?

Question

Quizplus · Accepted Answer

Use the combined gas law equation: 
(P₁V₁/T₁) = (P₂V₂/T₂)
Substitute in the given values: 
(0.900 atm)(2.50 L)/(295 K) = P₂(1.50 L)/(329.5 K)
Solve for P₂:
P₂ = (0.900 atm)(2.50 L)(329.5 K)/(295 K)(1.50 L) = 1.68 atm
Therefore, the pressure will be 1.68 atm when the temperature is changed to 56.5°C and the volume is changed to 1.50 L. The answer is choice C.

A Sample of Gas Initially Occupies 2