Propane burns in air according to the equation:
C₃H₈(g)+ 5O₂(g)→ 3CO₂(g)+ 4H₂O(g)
What volume of O₂ in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions?

Question

Quizplus · Accepted Answer

The Answer of Propane burns in air according to the equation: C₃H₈(g)+ 5O₂(g)→ 3CO₂(g)+ 4H₂O(g) What volume of O₂ in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions?

Propane Burns in Air According to the Equation