Consider the reaction between acetylene, C₂H₂, and oxygen in a welding torch: 2C₂H₂(g)+ 5O₂(g)→ 4CO₂(g)+ 2H₂O(g)If 5.4 moles of acetylene react with sufficient oxygen, how many grams of CO₂ should form?

Question

Quizplus · Accepted Answer

Using the mole ratio from the balanced equation, we can calculate the moles of COS produced: 5.4 mol C₂H₂ x (4 mol CO₂ / 2 mol C₂H₂) = 10.8 mol CO₂ Now, using the molar mass of COS (56.077 g/mol): 10.8 mol CO₂ x 56.077 g/mol = 605.5 g Rounding to the correct number of significant figures gives the final answer of 4.8 x 10² g.

Consider the Reaction Between Acetylene, C2H2, and Oxygen in a Welding

Consider the Reaction Between Acetylene, C₂H₂, and Oxygen in a Welding