When copper reacts with sulfur at high temperature, copper(I)sulfide is formed. 2Cu(s)+ S(s)→ Cu₂S(s)If the mass of the Cu₂S formed is 1.17 g, what mass of copper should have reacted?

Question

Quizplus · Accepted Answer

The reaction between copper and sulfur to form copper(I) sulfide (Cu2S) can be represented as 2Cu + S → Cu2S. The molar mass of Cu2S (copper(I) sulfide) can be calculated using the atomic masses of copper (Cu, approximately 63.5 g/mol) and sulfur (S, approximately 32.1 g/mol). Thus, the molar mass of Cu2S is approximately 2*63.5 + 32.1 = 159.1 g/mol. Given that 1.17 g of Cu2S is formed, we can calculate the moles of Cu2S produced as 1.17 g / 159.1 g/mol = 0.00735 mol. Since the stoichiometry of the reaction requires 2 moles of Cu to produce 1 mole of Cu2S, the moles of Cu reacted would be 2 * 0.00735 mol = 0.0147 mol. The mass of Cu that reacted can then be calculated by multiplying the moles of Cu by its molar mass (63.5 g/mol), resulting in 0.0147 mol * 63.5 g/mol = 0.934 g.

When Copper Reacts with Sulfur at High Temperature, Copper(I)sulfide Is