Consider the reaction between hydrogen and oxygen gases to form water: 2H₂(g)+ O₂(g)→ 2H₂O(l)If 8.5 moles of oxygen react with sufficient hydrogen, how many grams of water should form?

Question

Quizplus · Accepted Answer

First, we need to use stoichiometry to find the number of moles of water produced:

1 mole of O2 reacts with 2 moles of H2 to produce 2 moles of H2O
Therefore, 8.5 moles of O2 will react with 17 moles of H2 to produce 17 moles of H2O

Next, use the molar mass of water to convert moles to grams:

Molar mass of H2O = 18.015 g/mol
17 mol H2O x 18.015 g/mol = 306.26 g

Therefore, 306.26 g of water should form. However, none of the answer choices match this value exactly.

To determine the best answer choice, we can use estimation.

- A) 0.94 g: This value is much too small.
- B) 0.47 g: This value is also too small.
- C) 0.76 g: This value is too small as well.
- D) 3.1 x 10^12 g: This value is too large.
- E) 1.5 x 10^12 g: This value is also too large.

Therefore, the best answer choice is (D) 3.1 x 10^12 g, as it is the closest to the calculated value of 306.26 g.

Consider the Reaction Between Hydrogen and Oxygen Gases to Form