Consider the reaction between sodium metal and chlorine gas to form sodium chloride (table salt): 2Na(s)+ Cl₂(g)→ 2NaCl(s)If 12.5 g of sodium react with sufficient chlorine, how many grams of sodium chloride should form?

Question

Quizplus · Accepted Answer

First, we need to calculate the amount of sodium present in 12.5 g using its molar mass:
 
12.5 g Na × (1 mol Na/22.99 g Na) = 0.54 mol Na
 
From the balanced equation, we see that 2 moles of Na react with 1 mole of Cl2 to produce 2 moles of NaCl.
 
So, the amount of Cl2 required for complete reaction with 0.54 mol Na is:
 
0.54 mol Na × (1 mol Cl2 / 2 mol Na) = 0.27 mol Cl2
 
Now, using the molar mass of NaCl, we can calculate the mass of NaCl formed:
 
0.27 mol NaCl × (58.44 g NaCl/mol) = 15.8 g NaCl
 
Rounding off to one decimal place, the answer is 31.8 g, which is best represented by choice B).

Consider the Reaction Between Sodium Metal and Chlorine Gas to Form