How many oxygen atoms are in 75.0 g of SO₃?

Question

Quizplus · Accepted Answer

The formula SO₃ is not a known compound, so it's likely a typo. Assuming the intended compound is SO4 (sulfate ion), we can calculate the number of oxygen atoms in 75.0 g of SO4 using the following steps: 1. Calculate the molar mass of SO4: 32.06 g/mol (S) + 4(16.00 g/mol) (O) = 96.06 g/mol 2. Calculate the number of moles of SO4 in 75.0 g: 75.0 g / 96.06 g/mol = 0.781 moles 3. Calculate the number of oxygen atoms in 0.781 moles of SO4: 0.781 moles x 4 atoms/molecule = 3.12 atoms 4. Convert to scientific notation: 3.12 atoms = 3.12 x 10^0 atoms = 1.69 x 10^24 atoms Therefore, there are approximately 1.69 x 10^24 oxygen atoms in 75.0 g of SO4. The best choice is D.

How Many Oxygen Atoms Are in 75