How many nitrate ions are in 75.0 g of Zn(NO₃)₂?

Question

Quizplus · Accepted Answer

To determine the number of nitrate ions, we need to first find the number of moles of Zn(NO₃)₂, and then use the mole ratio to find the number of nitrate ions. The molar mass of Zn(NO₃)₂ is: 1 x 65.38 g/mol (Zn) + 1 x 14.01 g/mol (N) + 4 x 16.00 g/mol (O) + 1 x 32.06 g/mol (S) = 287.56 g/mol Next, we can use the molar mass to convert the given mass of 75.0 g to moles: 75.0 g Zn(NO₃)₂ / 287.56 g/mol = 0.2605 mol Zn(NO₃)₂ From the chemical formula, we see that there are 2 nitrate ions for every Zn(NO₃)₂ molecule. Therefore, the total number of nitrate ions is: 0.2605 mol Zn(NO₃)₂ x 2 mol NO3- / 1 mol Zn(NO₃)₂ x 6.022 x 10^23 ions/mol = 3.13 x 10^23 ions, which is closest to choice D, 4.77 x 10^23 atoms.

How Many Nitrate Ions Are in 75