To obtain 0.50 moles of potassium nitrate from a solution, you could either use 100.0 mL of a 5.0 M solution, or 250.0 mL of a 2.0 M solution.

Question

Quizplus · Accepted Answer

First, we need to calculate the amount of potassium nitrate required to obtain 0.50 moles:

Amount of potassium nitrate = moles x molar mass
= 0.50 mol x 101.1 g/mol (molar mass of KNO3)
= 50.55 g

Now, let's see which option would provide us with 50.55 g of potassium nitrate:

Option 1: Using 100.0 mL of a 5.0 M solution
The number of moles of potassium nitrate in 100.0 mL of a 5.0 M solution can be calculated as follows:

moles = Molarity x Volume (in L)
= 5.0 mol/L x 100.0 mL/1000 mL/L
= 0.50 mol

Therefore, using 100.0 mL of a 5.0 M solution would give us exactly 0.50 moles of potassium nitrate.

Option 2: Using 250.0 mL of a 2.0 M solution
The number of moles of potassium nitrate in 250.0 mL of a 2.0 M solution can be calculated as follows:

moles = Molarity x Volume (in L)
= 2.0 mol/L x 250.0 mL/1000 mL/L
= 0.50 mol

Therefore, using 250.0 mL of a 2.0 M solution would also give us exactly 0.50 moles of potassium nitrate.

Since both options give us the same amount of potassium nitrate, the statement is true.

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