TABLE 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture. She performs a two-tail test of the null hypothesis that the mean for the stressed oak furniture is 650. The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Table 9-6, if the test is performed with a level of significance of 0.10, the engineer can conclude that the mean amount of force necessary to produce cracks in stressed oak furniture is 650.

Question

Quizplus · Accepted Answer

Since the p-value (0.080) is less than the level of significance (0.10), the null hypothesis that the mean is 650 is rejected.

TABLE 9-6 The Quality Control Engineer for a Furniture Manufacturer Is Interested