TABLE 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture. She performs a two-tail test of the null hypothesis that the mean for the stressed oak furniture is 650. The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Table 9-6, if the test is performed with a level of significance of 0.05, the null hypothesis would be rejected.

Question

Quizplus · Accepted Answer

Looking at Table 9-6, we find that the critical value for a two-tail test at a significance level of 0.05 is ±1.96. Since the calculated value of the Z test statistic is not large enough to fall beyond the critical values, we fail to reject the null hypothesis. Therefore, the statement is false.

TABLE 9-6 The Quality Control Engineer for a Furniture Manufacturer Is Interested