What is the energy of the first rotational state of the hydrogen (H₂) molecule? The separation between the protons is 10−¹⁰ m and the mass of each proton is 1.67 × 10−²⁷ kg. (h = 6.626 × 10−³⁴ J ⋅ s and 1 eV = 1.6 × 10−¹⁹ J.)

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The Answer of What is the energy of the first rotational state of the hydrogen (H₂) molecule? The separation between the protons is 10−¹⁰ m and the mass of each proton is 1.67 × 10−²⁷ kg. (h = 6.626 × 10−³⁴ J ⋅ s and 1 eV = 1.6 × 10−¹⁹ J.)

What Is the Energy of the First Rotational State of the Hydrogen