Charge in an electric field: A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (mproton = 1.67 × 10-27 kg, e = 1.60 × 10-19C)
A) 6.71 × m/
opposite to the electric field
B) 6.71 × m/
opposite to the electric field
C) 6.71 × m/
in the direction of the electric field
D) 67.1 × m/
opposite to the electric field
Correct Answer:
Verified
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