Electric field of a single point-charge: The electric field 1.5 cm from a very small charged object points toward the object with a magnitude of 180,000 N/C. What is the charge on the object? (k = 1/4πε₀ = 8.99 × 10⁹ N ∙ m²/C²) A) - 4.5 nC B) + 4.5 nC C) - 5.0 nC D) + 5.0 nC

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The electric field E is given by E = kq/r^2, where k is Coulomb's constant (8.99 × 10^9 N·m^2/C^2), q is the charge, and r is the distance from the charge (1.5 cm = 0.015 m). The direction of the electric field towards the object indicates a negative charge. Solving for q gives q = Er^2/k. Substituting the given values, q = (180,000 N/C)(0.015 m)^2 / (8.99 × 10^9 N·m^2/C^2) = -4.5 × 10^-9 C = -4.5 nC.

Electric Field of a Single Point-Charge: the Electric Field 1