Consider the following partial ANOVA table: The numerator and denominator degrees of freedom (identified by asterisks) are:
A) 4 and 15
B) 3 and 16
C) 15 and 4
D) 16 and 3
E) 6 and 16

Question

Consider the following partial ANOVA table:  The numerator and denominator degrees of freedom (identified by asterisks) are:
A) 4 and 15 
B) 3 and 16 
C) 15 and 4 
D) 16 and 3 
E) 6 and 16

Quizplus · Accepted Answer

In the partial ANOVA table, the numerator degrees of freedom for the Treatment is 3 and for the Error is (16-3) = 13. The denominator degrees of freedom for the F-test of Treatment is (4-1) = 3 and for the F-test of Error is (16-4) = 12. Therefore, the answer is option B, with numerator degrees of freedom being 3 and denominator degrees of freedom being 16.

Consider the Following Partial ANOVA Table: the Numerator and Denominator