When solutions of AgNO₃ and NaOH react, the balanced molecular equation is as follows: 2AgNO₃(aq) + 2NaOH(aq) → Ag₂O(s) + 2NaNO₃(aq) + H₂O(l)
How much Ag₂O is produced when 2.00 g of AgNO₃ and 0.300 g of NaOH react?

Question

Quizplus · Accepted Answer

First, determine the molar masses of AgNO3 (169.87 g/mol) and NaOH (40.00 g/mol). Then, calculate the moles of each reactant: 2.00 g AgNO3 / 169.87 g/mol = 0.0118 mol AgNO3, and 0.300 g NaOH / 40.00 g/mol = 0.0075 mol NaOH. The reaction is limited by NaOH since it has fewer moles. The stoichiometry of the reaction shows that 2 moles of NaOH produce 1 mole of Ag2O, so 0.0075 mol NaOH will produce 0.00375 mol Ag2O. The molar mass of Ag2O is 231.74 g/mol, so the mass of Ag2O produced is 0.00375 mol * 231.74 g/mol = 0.869 g.

When Solutions of AgNO3 and NaOH React, the Balanced Molecular

When Solutions of AgNO₃ and NaOH React, the Balanced Molecular