Given the reaction 2HgO(s) → 2Hg(l) + O₂(g), what weight of elemental mercury will be obtained by the decomposition of 94.5 g of HgO?

Question

Quizplus · Accepted Answer

First, calculate the molar mass of HgO: Hg (200.59 g/mol) + O (16.00 g/mol) = 216.59 g/mol. Then, find the moles of HgO in 94.5 g: 94.5 g / 216.59 g/mol = 0.436 moles. The reaction shows that 2 moles of HgO produce 2 moles of Hg, so 0.436 moles of HgO will produce 0.436 moles of Hg. Finally, calculate the mass of Hg produced: 0.436 moles * 200.59 g/mol = 87.5 g.

Given the Reaction 2HgO(s) → 2Hg(l) + O2(g), What Weight

Given the Reaction 2HgO(s) → 2Hg(l) + O₂(g), What Weight