When solutions of AgNO₃ and NaCl react, the balanced molecular equation is as follows: AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
How much AgCl is produced when 3.10 g of AgNO₃ and 3.10 g of NaCl react?

Question

Quizplus · Accepted Answer

First, we need to determine which reactant is limiting. To do this, we can use stoichiometry and convert each reactant to the same product (AgCl). For AgNO₃: 3.10 g AgNO₃ x (1 mol AgNO₃/169.87 g AgNO₃) x (1 mol AgCl/1 mol AgNO₃) x (143.32 g AgCl/1 mol AgCl) = 2.62 g AgCl For NaCl: 3.10 g NaCl x (1 mol NaCl/58.44 g NaCl) x (1 mol AgCl/1 mol NaCl) x (143.32 g AgCl/1 mol AgCl) = 8.20 g AgCl Since AgNO₃ produces less AgCl than NaCl, it is the limiting reactant. Therefore, the amount of AgCl produced is 2.62 g.

When Solutions of AgNO3 and NaCl React, the Balanced Molecular

When Solutions of AgNO₃ and NaCl React, the Balanced Molecular