When solutions of AgNO₃ and NaCl react, the balanced molecular equation is as follows: AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
How much AgCl is produced when 3.10 g of AgNO₃ and 0.600 g of NaCl react?

Question

Quizplus · Accepted Answer

First, determine the molar masses of AgNO3 (169.87 g/mol) and NaCl (58.44 g/mol). Then, calculate the moles of each reactant (3.10 g AgNO3 / 169.87 g/mol = 0.0182 mol AgNO3; 0.600 g NaCl / 58.44 g/mol = 0.0103 mol NaCl). The reaction is 1:1, so NaCl is the limiting reactant. The moles of AgCl produced will be equal to the moles of NaCl reacted (0.0103 mol). The molar mass of AgCl is 143.32 g/mol, so the mass of AgCl produced is 0.0103 mol * 143.32 g/mol = 1.47 g.

When Solutions of AgNO3 and NaCl React, the Balanced Molecular

When Solutions of AgNO₃ and NaCl React, the Balanced Molecular