Lime, CaO, is produced by the reaction CaCO₃(s) → CaO(s) + CO₂(g). What weight of CO₂ is obtained by the decomposition of 38.7 g of CaCO₃?

Question

Quizplus · Accepted Answer

From the balanced chemical equation, we can see that the mole ratio of CaCO₃ to CO₂ is 1:1. Therefore, we can calculate the number of moles of CaCO₃: 38.7 g CaCO₃ x (1 mol CaCO₃/100.1 g CaCO₃) = 0.386 mol CaCO₃ Since the mole ratio of CaCO₃ to CO₂ is 1:1, the number of moles of CO₂ produced is also 0.386 mol. Finally, we can calculate the weight of CO₂ produced: 0.386 mol CO₂ x (44.01 g CO₂/1 mol CO₂) = 17.0 g CO₂. Therefore, the answer is B.

Lime, CaO, Is Produced by the Reaction CaCO3(s) → CaO(s)

Lime, CaO, Is Produced by the Reaction CaCO₃(s) → CaO(s)