When solutions of AgNO₃ and NaOH react, the balanced molecular equation is as follows: 2AgNO₃(aq) + 2NaOH(aq) → Ag₂O(s) + 2NaNO₃(aq) + H₂O(l)
How much Ag₂O is produced when 0.200 g of AgNO₃ and 0.200 g of NaOH react?

Question

Quizplus · Accepted Answer

First, we need to determine which reagent is limiting. From the balanced equation, 2 moles of AgNO₃ react with 2 moles of NaOH to produce 1 mole of Ag₂O. To determine the number of moles of each reagent, we can use the formula: moles = mass/molar mass For AgNO₃: moles = 0.200 g / 169.87 g/mol = 0.001177 moles For NaOH: moles = 0.200 g / 40.00 g/mol = 0.00500 moles Since AgNO₃ has fewer moles than NaOH, it is the limiting reagent. Using the mole ratio from the balanced equation: 1 mole Ag₂O : 2 moles AgNO₃ = x moles Ag₂O : 0.001177 moles x = 0.0005885 moles Ag₂O Finally, we can use the formula: mass = moles x molar mass mass = 0.0005885 moles x 247.80 g/mol = 0.1457 g Therefore, the answer is B) 0.136 g because we have two significant figures in the given masses, so our final answer should also have two significant figures.

When Solutions of AgNO3 and NaOH React, the Balanced Molecular

When Solutions of AgNO₃ and NaOH React, the Balanced Molecular