The balanced equation for burning octane is 2C₈H₁₈(g) + 25O₂(g) → 18H₂O(g) + 16CO₂(g). What weight of H₂O is produced by completely burning 19.8 g of octane?

Question

Quizplus · Accepted Answer

The balanced equation shows that 2 moles of octane (2 x 114 g = 228 g) produce 18 moles of water (18 x 18 g = 324 g). Therefore, 19.8 g of octane will produce (19.8 g / 228 g) x 324 g = 28.1 g of water.

The Balanced Equation for Burning Octane Is 2C8H18(g) + 25O2(g)

The Balanced Equation for Burning Octane Is 2C₈H₁₈(g) + 25O₂(g)