Given Cu2+(aq) + 2e- → Cu(s) E° = +0.34 V Al3+(aq) + 3e- → Al(s) E° = -1.66 V
Na+(aq) + e- → Na(s) E° = -2.71 V
Which of the following reactions will occur?
A) 2Na+(aq) + Cu(s) → Cu2+(aq) + 2Na(s)
B) Al(s) + 3Na+(aq) → Al3+(aq) + 3Na(s)
C) 2Na(s) + Cu2+(aq) → Cu(s) + 2Na+(aq)
D) 2Al3+(aq) + 3Cu(s) → 3Cu2+(aq) + 2Al(s)
E) None of these will occur.
Correct Answer:
Verified
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