For the following reaction, ΔP(C₆H₁₄)/Δt was found to be -6.2 × 10^-3 atm/s. C₆H₁₄(g) → C₆H₆(g) + 4H₂(g) Determine ΔP(H₂)/Δt for this reaction at the same time.

Question

Quizplus · Accepted Answer

For every mole of $ \text{CS}_2 $ that reacts, 4 moles of $ \text{H}_2 $ are produced. Therefore, if the rate of disappearance of $ \text{CS}_2 $ is $ -6.2 \times 10^{-3} $ atm/s, the rate of appearance of $ \text{H}_2 $ is 4 times that rate, which is $ 4 \times -6.2 \times 10^{-3} = -24.8 \times 10^{-3} $ atm/s. Since the rate of appearance is positive, the correct answer is $ 2.5 \times 10^{-2} $ atm/s after adjusting the decimal place correctly.

For the Following Reaction, ΔP(C6H14)/Δt Was Found to Be -6

For the Following Reaction, ΔP(C₆H₁₄)/Δt Was Found to Be -6