For the reaction C₆H₁₄(g) → C₆H₆(g) + 4H₂(g), ΔP(H₂)/Δt was found to be 2.5 × 10^-2 atm/s, where ΔP(H₂) is the change in pressure of hydrogen. Determine ΔP(C₆H₁₄)/Δt for this reaction at the same time.

Question

Quizplus · Accepted Answer

Given the stoichiometry of the reaction, for every 4 moles of H2 produced, 1 mole of CH4 is consumed. Therefore, the rate of change in pressure for CH4 will be one-fourth that of H2 but in the opposite direction (negative), making it -2.5 × 10^-2 atm/s ÷ 4 = -6.25 × 10^-3 atm/s, which is closest to choice B.

For the Reaction C6H14(g) → C6H6(g) + 4H2(g), ΔP(H2)/Δt Was

For the Reaction C₆H₁₄(g) → C₆H₆(g) + 4H₂(g), ΔP(H₂)/Δt Was