What would the concentration of OH- be if the concentration of H₃O+ was 1 × 10-8M? [H₃O+] × [OH-] = Kw = 1 × 10-14

Name: What would the concentration of OH- be if the concentration of H₃O+ was 1 × 10-8M? [H₃O+] × [OH-] = Kw = 1 × 10-14
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Given the ion product of water (Kw) is 1 × 10^-14, and the concentration of H₃O+ is 1 × 10^-8 M, the concentration of OH- can be found by dividing Kw by the concentration of H₃O+. Thus, [OH-] = 1 × 10^-14 / 1 × 10^-8 = 1 × 10^-6 M.

What Would the Concentration of OH- Be If the Concentration