What would the concentration of H₃O+ be if the concentration of OH- was 1 × 10-11M? [H₃O+] × [OH-] = Kw = 1 × 10-14

Name: What would the concentration of H₃O+ be if the concentration of OH- was 1 × 10-11M? [H₃O+] × [OH-] = Kw = 1 × 10-14
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Given the ion product of water (Kw) is 1 × 10^-14, and [OH^-] = 1 × 10^-11 M, solving for [H3O+] gives [H3O+] = Kw / [OH^-] = (1 × 10^-14) / (1 × 10^-11) = 1 × 10^-3 M.

What Would the Concentration of H₃O+ Be If the Concentration