Consider a chemical reaction that follows the equation NaHCO₃ + CH₃COOH → NaCH₃COO + CO₂ + H₂O. 80 g of NaHCO₃ and 65 g CH₃COOH is available for performing this reaction. Which of the following is considered to be in excess? (Molar masses: NaHCO₃ = 84 g; CH₃COOH = 60.05 g)

Question

Quizplus · Accepted Answer

Given the molar masses, we can calculate the moles of NaHCO3 and CH3COOH available. For NaHCO3: 80 g / 84 g/mol = 0.95 moles. For CH3COOH: 65 g / 60.05 g/mol = 1.08 moles. Since the reaction is likely to proceed on a 1:1 molar basis and there are more moles of CH3COOH, CH3COOH is in excess.

Consider a Chemical Reaction That Follows the Equation NaHCO3

Consider a Chemical Reaction That Follows the Equation NaHCO₃