A current-carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field.If the current is 10.0 A and it is determined that there is a resultant force of 3.0 N on the wire due to the interaction of the current and field,what is the magnetic field strength?

Question

Quizplus · Accepted Answer

The magnetic force on a current-carrying wire is given by F = BIL, where F is the force, B is the magnetic field strength, I is the current, and L is the length of the wire. Rearranging for B gives B = F / (IL). Substituting the given values: B = 3.0 N / (10.0 A * 0.5 m) = 0.60 T.

A Current-Carrying Wire of Length 50 Cm Is Positioned Perpendicular