Question 1

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the magnetic force on the proton to that on the deuteron is:

Accepted Answer

The magnetic force on a charged particle moving perpendicular to a uniform magnetic field is given by F = q*v*B, where q is the charge of the particle, v is its velocity, and B is the magnitude of the magnetic field. As both particles have the same charge and are moving with the same velocity, the only difference between them is their mass. Since the magnetic force is directly proportional to the charge and velocity of the particle but inversely proportional to its mass, the ratio of the magnetic force on the proton to that on the deuteron is 1.

Question 2

A circular loop carrying a current of 1.0 A is oriented in a magnetic field of 0.35 T.The loop has an area of 0.24 m² and is mounted on an axis,perpendicular to the magnetic field,which allows the loop to rotate.What is the torque on the loop when its plane is oriented at a 25 $\degree$ angle to the field?

Accepted Answer

The answer of A circular loop carrying a current of...

Question 3

A current-carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field.If the current is 10.0 A and it is determined that there is a resultant force of 3.0 N on the wire due to the interaction of the current and field,what is the magnetic field strength?

Accepted Answer

The magnetic force on a current-carrying wire is given by F = BIL, where F is the force, B is the magnetic field strength, I is the current, and L is the length of the wire. Rearranging for B gives B = F / (IL). Substituting the given values: B = 3.0 N / (10.0 A * 0.5 m) = 0.60 T.

Question 4

The force exerted on a current-carrying wire located in an external magnetic field is directly proportional to which of the following?

Accepted Answer

The force exerted on a current-carrying wire located in an external magnetic field is given by the equation F = BILsinθ, where B is the magnetic field strength, I is the current strength, L is the length of the wire within the magnetic field, and θ is the angle between the direction of the magnetic field and the direction of the current. Therefore, the force is directly proportional to both the current strength (I) and the field strength (B), so the correct choice is C.

Question 5

A rectangular coil (0.20 m x 0.80 m)has 200 turns and is in a uniform magnetic field of 0.30 T.If the orientation of the coil is varied through all possible positions,the maximum torque on the coil by magnetic forces is 0.080 N*m.What is the current in the coil?

Accepted Answer

The answer of A rectangular coil (0.20 m x 0.80...

Question 6

A circular current loop is placed in an external magnetic field.How is the torque related to the radius of the loop?

Accepted Answer

According to the formula for torque on a current loop in a magnetic field, τ = NIABsinθ, where N is the number of turns in the loop, I is the current flowing through the loop, A is the area of the loop, B is the magnetic field strength, and θ is the angle between the normal to the loop and the magnetic field direction. The area of a circular loop is proportional to the radius squared, so A ∝ r^2. Therefore, the torque is directly proportional to the radius squared.

Question 7

A circular loop carrying a current of 1.0 A is oriented in a magnetic field of 0.35 T.The loop has an area of 0.24 m² and is mounted on an axis,perpendicular to the magnetic field,which allows the loop to rotate.If the plane of the loop is oriented parallel to the field,what torque is created by the interaction of the loop current and the field?

Accepted Answer

The torque created by the interaction of the loop current and the magnetic field is given by the equation τ = NIABsinθ, where N is the number of turns in the loop (which is one in this case), I is the current, A is the area of the loop, B is the magnitude of the magnetic field, and θ is the angle between the normal to the plane of the loop and the direction of the magnetic field. 
Since the plane of the loop is oriented parallel to the field, θ = 0, and sinθ = 0. Therefore, the torque is zero.

Question 8

A circular coil (radius = 0.40 m)has 160 turns and is in a uniform magnetic field.If the orientation of the coil is varied through all possible positions,the maximum torque on the coil by magnetic forces is 0.16 N*m when the current in the coil is 4.0 mA.What is the magnitude of the magnetic field?

Accepted Answer

The answer of A circular coil (radius = 0.40 m)has...

Question 9

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the acceleration of the proton to that of the deuteron is:

Accepted Answer

The acceleration $a$ of a charged particle in a magnetic field is given by $a = \frac{F}{m}$, where $F = qvB$ is the magnetic force, $q$ is the charge, $v$ is the velocity, $B$ is the magnetic field strength, and $m$ is the mass of the particle. Since both the proton and the deuteron have the same charge and are moving with the same velocity in the magnetic field, the force $F$ on both particles is the same. However, the deuteron has twice the mass of the proton ($m_{deuteron} = 2m_{proton}$). Therefore, the acceleration of the proton is twice that of the deuteron, making the ratio of the acceleration of the proton to that of the deuteron $2:1$ or simply $2$.

Question 10

A horizontal wire of length 3.0 m carries a current of 6.0 A and is oriented so that the current direction is 50 $\degree$ S of W.The Earth's magnetic field is due north at this point and has a strength of 0.14 x 10^-4 T.What is the direction of the force on the wire?

Accepted Answer

According to the right hand rule, if you point your right thumb in the direction of the current and your fingers in the direction of the magnetic field, the resulting force will be perpendicular to both and will point toward your palm. Since the magnetic field is due north and the current is oriented 50 degrees south of west, the resulting force will point downward, toward the Earth's surface. Therefore, the correct answer is option B.

Question 11

A horizontal wire of length 3.0 m carries a current of 6.0 A and is oriented so that the current direction is 50 $\degree$ S of W.The Earth's magnetic field is due north at this point and has a strength of 0.14 x 10^-4 T.What is the size of the force on the wire?

Accepted Answer

The answer of A horizontal wire of length 3.0 m...

Question 12

There is a current I flowing in a clockwise direction in a square loop of wire that is in the plane of the paper.If the magnetic field B is toward the right,and if each side of the loop has length L,then the net magnetic torque acting on the loop is:

Accepted Answer

The answer of There is a current I flowing in...

Question 13

A 2.0-m wire segment carrying a current of 0.60 A oriented parallel to a uniform magnetic field of 0.50 T experiences a force of what magnitude?

Accepted Answer

The force on a current-carrying wire in a magnetic field is given by F = I * L * B * sin(θ). Since the wire is parallel to the magnetic field, θ = 0 degrees, and sin(0) = 0, resulting in a force of zero.

Question 14

There is a current I flowing in a clockwise direction in a square loop of wire that is in the plane of the paper.If the magnetic field B is toward the right,and if each side of the loop has length L,then the net magnetic force acting on the loop is:

Accepted Answer

The magnetic force on a current-carrying wire is given by F = ILB sinθ, where I is the current, L is the length of the wire, B is the magnetic field, and θ is the angle between the direction of the current and the magnetic field. In this case, the angle θ between the direction of the current and the magnetic field is 90 degrees, so sinθ = 1. Therefore, the net magnetic force on the loop is F = ILB, and since the forces on opposite sides of the loop are equal and opposite, they cancel out, leading to a net force of zero. Therefore, the correct answer is D.

Question 15

There is a magnetic force on a particle.It is possible that the particle is:

Accepted Answer

The answer of There is a magnetic force on a...

Question 16

A copper wire of length 25 cm is in a magnetic field of 0.20 T.If it has a mass of 10 g,what is the minimum current through the wire that would cause a magnetic force equal to its weight?

Accepted Answer

The magnetic force on a current-carrying wire in a magnetic field is given by:

F = BIL

where F is the magnetic force, B is the magnetic field, I is the current, and L is the length of the wire in the magnetic field.

We want to find the minimum current that will produce a magnetic force equal to the weight of the wire. The weight is given by:

W = mg

where W is the weight, m is the mass, and g is the acceleration due to gravity.

Setting these two expressions equal, we have:

BIL = mg

Solving for I, we get:

I = mg/BL

Plugging in the given values, we get:

I = (0.01 kg)(9.8 m/s^2)/(0.2 T)(0.25 m) = 2.0 A

Therefore, the minimum current that will produce a magnetic force equal to the weight of the wire is 2.0 A, which corresponds to choice C.

Question 17

The direction of the force on a current carrying wire located in an external magnetic field is which of the following?

Accepted Answer

The force on a current-carrying wire located in an external magnetic field is given by the cross product of the current and the magnetic field. Since the cross product always results in a vector that is perpendicular to both the current and the magnetic field, the force must be perpendicular to both. Therefore, both choices A and B are valid.

Question 18

Which of the following devices makes use of an electromagnet?

Accepted Answer

Both loudspeaker and galvanometer make use of an electromagnet. In a loudspeaker, the electromagnet is used to move a diaphragm and produce sound waves. In a galvanometer, the electromagnet is used to deflect a coil of wire and measure electric current.

Question 19

A wire is lying horizontally in the north-south direction and the horizontal magnetic field is toward the east.Some positive charges in the wire move north and an equal number of negative charges move south.The direction of the force on the wire will be:

Accepted Answer

The answer of A wire is lying horizontally in the...

Question 20

An electron moves through a region of crossed electric and magnetic fields.The electric field E = 2 000 V/m and is directed straight down.The magnetic field B = 0.80 T and is directed to the left.For what velocity v of the electron into the paper will the electric force exactly cancel the magnetic force?

Accepted Answer

The answer of An electron moves through a region of...

Quiz 19: Magnetism

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the magnetic force on the proton to that on the deuteron is:

A current-carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field.If the current is 10.0 A and it is determined that there is a resultant force of 3.0 N on the wire due to the interaction of the current and field,what is the magnetic field strength?

The force exerted on a current-carrying wire located in an external magnetic field is directly proportional to which of the following?

A rectangular coil (0.20 m x 0.80 m) has 200 turns and is in a uniform magnetic field of 0.30 T.If the orientation of the coil is varied through all possible positions,the maximum torque on the coil by magnetic forces is 0.080 N*m.What is the current in the coil?

A circular current loop is placed in an external magnetic field.How is the torque related to the radius of the loop?

A circular coil (radius = 0.40 m) has 160 turns and is in a uniform magnetic field.If the orientation of the coil is varied through all possible positions,the maximum torque on the coil by magnetic forces is 0.16 N*m when the current in the coil is 4.0 mA.What is the magnitude of the magnetic field?

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the acceleration of the proton to that of the deuteron is:

A horizontal wire of length 3.0 m carries a current of 6.0 A and is oriented so that the current direction is 50 $\degree$ S of W.The Earth's magnetic field is due north at this point and has a strength of 0.14 x 10^-4 T.What is the direction of the force on the wire?

A horizontal wire of length 3.0 m carries a current of 6.0 A and is oriented so that the current direction is 50 $\degree$ S of W.The Earth's magnetic field is due north at this point and has a strength of 0.14 x 10^-4 T.What is the size of the force on the wire?

There is a current I flowing in a clockwise direction in a square loop of wire that is in the plane of the paper.If the magnetic field B is toward the right,and if each side of the loop has length L,then the net magnetic torque acting on the loop is:

A 2.0-m wire segment carrying a current of 0.60 A oriented parallel to a uniform magnetic field of 0.50 T experiences a force of what magnitude?

There is a current I flowing in a clockwise direction in a square loop of wire that is in the plane of the paper.If the magnetic field B is toward the right,and if each side of the loop has length L,then the net magnetic force acting on the loop is:

There is a magnetic force on a particle.It is possible that the particle is:

A copper wire of length 25 cm is in a magnetic field of 0.20 T.If it has a mass of 10 g,what is the minimum current through the wire that would cause a magnetic force equal to its weight?

The direction of the force on a current carrying wire located in an external magnetic field is which of the following?

Which of the following devices makes use of an electromagnet?

A wire is lying horizontally in the north-south direction and the horizontal magnetic field is toward the east.Some positive charges in the wire move north and an equal number of negative charges move south.The direction of the force on the wire will be:

Quiz 19: Magnetism

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the magnetic force on the proton to that on the deuteron is:

A current-carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field.If the current is 10.0 A and it is determined that there is a resultant force of 3.0 N on the wire due to the interaction of the current and field,what is the magnetic field strength?

The force exerted on a current-carrying wire located in an external magnetic field is directly proportional to which of the following?

A rectangular coil (0.20 m x 0.80 m) has 200 turns and is in a uniform magnetic field of 0.30 T.If the orientation of the coil is varied through all possible positions,the maximum torque on the coil by magnetic forces is 0.080 N*m.What is the current in the coil?

A circular current loop is placed in an external magnetic field.How is the torque related to the radius of the loop?

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the acceleration of the proton to that of the deuteron is:

A horizontal wire of length 3.0 m carries a current of 6.0 A and is oriented so that the current direction is 50 °\degree° S of W.The Earth's magnetic field is due north at this point and has a strength of 0.14 x 10-4 T.What is the direction of the force on the wire?

A horizontal wire of length 3.0 m carries a current of 6.0 A and is oriented so that the current direction is 50 °\degree° S of W.The Earth's magnetic field is due north at this point and has a strength of 0.14 x 10-4 T.What is the size of the force on the wire?

There is a current I flowing in a clockwise direction in a square loop of wire that is in the plane of the paper.If the magnetic field B is toward the right,and if each side of the loop has length L,then the net magnetic torque acting on the loop is:

A 2.0-m wire segment carrying a current of 0.60 A oriented parallel to a uniform magnetic field of 0.50 T experiences a force of what magnitude?

There is a current I flowing in a clockwise direction in a square loop of wire that is in the plane of the paper.If the magnetic field B is toward the right,and if each side of the loop has length L,then the net magnetic force acting on the loop is:

There is a magnetic force on a particle.It is possible that the particle is:

A copper wire of length 25 cm is in a magnetic field of 0.20 T.If it has a mass of 10 g,what is the minimum current through the wire that would cause a magnetic force equal to its weight?

The direction of the force on a current carrying wire located in an external magnetic field is which of the following?

Which of the following devices makes use of an electromagnet?

A wire is lying horizontally in the north-south direction and the horizontal magnetic field is toward the east.Some positive charges in the wire move north and an equal number of negative charges move south.The direction of the force on the wire will be:

A horizontal wire of length 3.0 m carries a current of 6.0 A and is oriented so that the current direction is 50 $\degree$ S of W.The Earth's magnetic field is due north at this point and has a strength of 0.14 x 10^-4 T.What is the direction of the force on the wire?

A horizontal wire of length 3.0 m carries a current of 6.0 A and is oriented so that the current direction is 50 $\degree$ S of W.The Earth's magnetic field is due north at this point and has a strength of 0.14 x 10^-4 T.What is the size of the force on the wire?