What is the total resistance of three resistors--3 k$\Omega$, 4 k$\Omega$, and 12 k$\Omega$--connected in parallel?
A) 1.5 k$\Omega$
B) 2 k$\Omega$
C) 5 k$\Omega$
D) 6.3 k$\Omega$

Question

Quizplus · Accepted Answer

The total resistance $R_{total}$ of resistors in parallel is given by $\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$. For 3 kΩ, 4 kΩ, and 12 kΩ, $\frac{1}{R_{total}} = \frac{1}{3} + \frac{1}{4} + \frac{1}{12} = \frac{4+3+1}{12} = \frac{2}{3}$. Therefore, $R_{total} = \frac{3}{2} = 1.5$ kΩ.

What Is the Total Resistance of Three Resistors--3 K Ω\OmegaΩ , 4 K

What Is the Total Resistance of Three Resistors--3 K $\Omega$ , 4 K