Three resistors--1 k $\Omega$, 2 k $\Omega$, and 7 k $\Omega$--are connected in series. What is the total circuit resistance?
A) 0.55 $\Omega$
B) 1.83 $\Omega$
C) 4 k $\Omega$
D) 10 k $\Omega$

Question

Three resistors--1 k $\Omega$, 2 k $\Omega$, and 7 k $\Omega$--are connected in series. What is the total circuit resistance?
A) 0.55  $\Omega$
B) 1.83 $\Omega$
C) 4 k $\Omega$
D) 10 k $\Omega$

Quizplus · Accepted Answer

When resistors are connected in series, the total resistance is the sum of the individual resistances. Therefore, the total resistance is 1 kΩ + 2 kΩ + 7 kΩ = 10 kΩ.

Three Resistors--1 K Ω\OmegaΩ , 2 K Ω\OmegaΩ , and 7 K Ω\OmegaΩ

Three Resistors--1 K $\Omega$ , 2 K $\Omega$ , and 7 K $\Omega$