A series circuit consists of a 10 $\Omega$resistor, a 20 $\Omega$ resistor, and a 30 $\Omega$resistor. The circuit is connected to a 120 V source. If the voltage across the 10 $\Omega$resistor measures 20 V and the voltage across the 30 $\Omega$ resistor measures 60 V, how much voltage should be measured across the 20 $\Omega$ resistor?
A) There is not enough information given to solve this problem.
B) 120 V
C) 40 V
D) 10 V

Question

A series circuit consists of a 10  $\Omega$resistor, a 20  $\Omega$ resistor, and a 30  $\Omega$resistor. The circuit is connected to a 120 V source. If the voltage across the 10  $\Omega$resistor measures 20 V and the voltage across the 30  $\Omega$ resistor measures 60 V, how much voltage should be measured across the 20  $\Omega$ resistor?
A) There is not enough information given to solve this problem.
B) 120 V
C) 40 V
D) 10 V

Quizplus · Accepted Answer

Since this is a series circuit, the total voltage of the circuit is the sum of the voltages across each resistor. Therefore, the voltage across the 10 F1F1F1S1F1F1F10 resistor, the voltage across the 20 F1F1F1S1F1F1F10 resistor, and the voltage across the 30 F1F1F1S1F1F1F10 resistor will add up to 120 V. We know the voltage across the 10 F1F1F1S1F1F1F10 resistor is 20 V, and the voltage across the 30 F1F1F1S1F1F1F10 resistor is 60 V, so the voltage across the 20 F1F1F1S1F1F1F10 resistor must be 40 V (120 V - 20 V - 60 V = 40 V). Therefore, the answer is C.

A Series Circuit Consists of a 10 Ω\OmegaΩ Resistor, a 20 Ω\OmegaΩ

A Series Circuit Consists of a 10 $\Omega$ Resistor, a 20 $\Omega$