If four 0.022 $\mu \mathrm { F }$ capacitors are connected in parallel,$\mathrm { C_T }$ equals_______
A) 0.022 $\mu \mathrm { F }$
B) 0.049 $\mu \mathrm { F }$
C) 0.088 $\mu \mathrm { F }$
D) 0.044 $\mu \mathrm { F }$

Question

If four  0.022 $\mu \mathrm { F }$ capacitors are connected in parallel,$\mathrm { C_T }$ equals_______
A)  0.022 $\mu \mathrm { F }$
B)  0.049 $\mu \mathrm { F }$
C)  0.088 $\mu \mathrm { F }$
D)  0.044 $\mu \mathrm { F }$

Quizplus · Accepted Answer

When capacitors are connected in parallel, the total capacitance is simply the sum of the individual capacitances. Therefore:
\begin{align*}
C_{T} &= 4 \times 0.022\mu F \
&= 0.088\mu F
\end{align*}
Therefore, the correct choice is C, 0.088 $\mu \mathrm { F }$.

If Four 0 μF\mu \mathrm { F }μF Capacitors Are Connected in Parallel

If Four 0 $\mu \mathrm { F }$ Capacitors Are Connected in Parallel