What is the capacitance that stores 1.175 $\mu \mathrm { C }$ of charge and drops 25 V?
A) 0.47 $\mu F$
B) 0.047 $\mu \mathrm { F }$
C) 4.7 $\mu \mathrm { F }$
D) 47 $\mu \mathrm { F }$

Question

What is the capacitance that stores  1.175  $\mu \mathrm { C }$ of charge and drops 25 V?
A)  0.47 $\mu F$
B)  0.047  $\mu \mathrm { F }$
C)  4.7  $\mu \mathrm { F }$
D) 47 $\mu \mathrm { F }$

Quizplus · Accepted Answer

We can use the formula for capacitance:

$$C = \frac{Q}{V}$$

where Q is the charge stored and V is the voltage drop across the capacitor. Plugging in the given values, we get:

$$C = \frac{1.175 \mu C}{25 V} = 0.047 \mu F$$

Therefore, the answer is B, 0.047 $\mu$F.

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