What is the instantaneous voltage at 17° on a 169 V_P sine wave? A) 49.4 V B) 80.5 V C) 161 V D) 98.8 V

Name: What is the instantaneous voltage at 17° on a 169 V P sine wave? A) 49.4 V B) 80.5 V C) 161 V D) 98.8 V
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The instantaneous voltage of a sine wave is given by V = Vp * sin(θ), where Vp is the peak voltage and θ is the angle in degrees. For a 169 V peak sine wave at 17°, V = 169 * sin(17°) ≈ 49.4 V.

What Is the Instantaneous Voltage at 17° on a