An oscilloscope's seconds/division switch is set on 20 $\mu \mathrm { s } / \mathrm { cm }$ . If the trace is 7.5 cm long, what is the period?
A) 150 $\mu \mathrm { s }$
B) 1.5
C) 5 $\mu \mathrm { s }$
D) 0.0015 s

Question

An oscilloscope's seconds/division switch is set on 20 $\mu \mathrm { s } / \mathrm { cm }$ . If the trace is  7.5 cm long, what is the period?
A) 150 $\mu \mathrm { s }$ 
B) 1.5 
C) 5 $\mu \mathrm { s }$ 
D) 0.0015 s

Quizplus · Accepted Answer

The length of a single division on the screen is 20 $\mu \mathrm { s }$. Since the trace is 7.5 cm long, the time taken for the trace to cover this distance is 7.5 x 20 = 150 $\mu \mathrm { s }$. Therefore, the period of the waveform is also 150 $\mu \mathrm { s }$.

An Oscilloscope's Seconds/division Switch Is Set on 20 μs/cm\mu \mathrm { s } / \mathrm { cm }μs/cm

An Oscilloscope's Seconds/division Switch Is Set on 20 $\mu \mathrm { s } / \mathrm { cm }$