An inductor has an inductance of 0.8 H and is connected to a 120-V, 60-Hz line. How much current will flow in this circuit if the wire resistance of the inductor is negligible?
A) 0.398 A
B) 0.796 A
C) 1.25 A
D) 2.51 A

Question

Quizplus · Accepted Answer

The current in an inductor can be calculated using the formula $I = \frac{V}{X_L}$, where $I$ is the current, $V$ is the voltage, and $X_L$ is the inductive reactance. The inductive reactance $X_L$ is given by $X_L = 2\pi fL$, where $f$ is the frequency and $L$ is the inductance. Substituting the given values, $X_L = 2\pi(60)(0.8) = 301.6 \Omega$. Therefore, the current $I = \frac{120}{301.6} = 0.398 A$.

An Inductor Has an Inductance of 0