Three inductors are connected in parallel. Inductor 1 has an inductance of 2.5 H, inductor 2 has an inductance of 1.8 H, and inductor 3 has an inductance of 1.2 H. The total inductance of this circuit is ____H.
A) 0.186
B) 0.559
C) 1.789
D) 5.5

Question

Quizplus · Accepted Answer

The total inductance $L_{total}$ of inductors in parallel is given by the reciprocal of the sum of the reciprocals of their individual inductances: $1/L_{total} = 1/L_1 + 1/L_2 + 1/L_3$. Plugging in the given values: $1/L_{total} = 1/2.5 + 1/1.8 + 1/1.2$. Solving this gives $L_{total} \approx 0.559$ H.

Three Inductors Are Connected in Parallel