What value of Z (atomic number) and A (mass number) result in the following alpha decay? ${ }_{92}^{238} \mathrm{U} \rightarrow{ }_{Z}^{A} \mathrm{X}+\alpha$
A)Z = 92; A = 238
B)Z = 91; A = 238
C)Z = 90; A = 234
D)Z = 93; A = 238
E)Z = 88; A = 236

Question

Quizplus · Accepted Answer

The Answer is C

What Value of Z (Atomic Number) and a (Mass Number) 92238U→ZAX+α{ }_{92}^{238} \mathrm{U} \rightarrow{ }_{Z}^{A} \mathrm{X}+\alpha92238​U→ZA​X+α

What Value of Z (Atomic Number) and a (Mass Number) ${ }_{92}^{238} \mathrm{U} \rightarrow{ }_{Z}^{A} \mathrm{X}+\alpha$