The magnitude of the spin angular momentum for an electron is equal to:
C)/2
D)($\pm$/2 )

Question

The magnitude of the spin angular momentum for an electron is equal to:
C)/2 
D)($\pm$/2 )

Quizplus · Accepted Answer

The magnitude of the spin angular momentum for an electron is equal to the square root of (s(s+1)ħ^2), where s is the spin quantum number which is equal to 1/2 for electrons. Therefore, the magnitude of the spin angular momentum for an electron is equal to the square root of (1/2(1/2+1)ħ^2) = ħ/2 = 11eb8aea_06d0_32ca_8952_67df7254a244_TB8846_11. Choice B matches this value.

The Magnitude of the Spin Angular Momentum for an Electron ±\pm±

The Magnitude of the Spin Angular Momentum for an Electron $\pm$