An ac generator with peak voltage 100 volts is placed across a 10- $\Omega$ resistor.What is the average power dissipated?
A)100 W
B)150 W
C)500 W
D)1000 W
E)2000 W

Question

Quizplus · Accepted Answer

The formula for average power dissipated in a resistor is P = V^2/R. Plugging in the given values, we get P = (100 V)^2/(10 Ω) = 1000 W. However, this is the peak power, and since the generator is AC, the power fluctuates over time. To find the average, we need to divide by 2, which gives us 500 W. Therefore, the answer is C, 500 W.

An Ac Generator with Peak Voltage 100 Volts Is Placed Ω\OmegaΩ

An Ac Generator with Peak Voltage 100 Volts Is Placed $\Omega$